Binary numbers are the utmost basics of computers. In essence, every image, file, or anything on your computer can be translated into 0s and 1s.
So what are these binary numbers and how do you read them?
Well, binary numbers are basically numbers based on zeros and ones instead of regular 0 through 9 numbers.
For example, here’s a binary number:
01010
You always count from the right.
The first 0 from the right can be either 0 or 1. (in this case it’s 0)
The second 1 from the right can be either 0 or 2. (in this case it’s 2)
The third 0 from the right can be either 0 or 4 (in this case it’s 0)
The fourth 1 from the right can be either 0 or 8 (in this case it’s 8)
The fifth 0 from the right can be either 0 or 16 (in this case it’s 0)
As you can see every binary number is multiplied by 2 from the right to left.
If it’s a 1, you add the large number else it stays at zero.
So 01010 = 2+8=16.
Or you can also write as 1010.
Here’s another example of writing 9:
1001
Well, if you don’t understand it still, try reading this on Wikipedia or watch the video below:
video://www.youtube.com/watch?v=qdFmSlFojIw
4 Responses to Binary Numbers DIY – How to Read Binary Numbers!
Leave a Reply
1010 = 10
0001 0000 = 16
Oh yeah, you know what, I am a bad teacher! hahaha! 10!
It’s just another number base. Using base-ten characters, (in other words, the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9,) the binary “equivalent” can be figured by balancing a (fairly) simple equation:
base-ten (decimal) = base-two (binary)
xn^10 = xn^2
x = the coefficient, also the digit; 1 or 0 for binary, 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9 for decimal
n = place position (thus n^10 = place value for decimal and n^2 = place value for binary)
Note that I put “equivalent” in quotes – it is equivalent, but really, it’s just another way of writing the exact same thing. It’s more like the difference between writing “1020.0500” and “1.0200500*10^3” than than it is to “1020.0500” and “1000 + 80.05 – 60”.
Also, I realize that this is essentially re-stating what the video said, but if it helps anyone understand it any better, than it was worth it (to me) to post this comment.
Great, thanks for that, I am sure it will help more people.